Which of the following compound will given yellow precipitate on shaking with aqueous solution of NaOH followed by the addition of `AgNO_(3)` solution ?

Options

A.
B.
C.
D.

Answer

To determine which compound will give a yellow precipitate when shaken with an aqueous solution of NaOH followed by the addition of AgNO₃, we can follow these steps:

### Step 1: Identify the Compounds
First, we need to identify the compounds given in the question. Let's assume we have the following compounds to analyze:
1. Compound A
2. Compound B
3. Compound C
4. Compound D

### Step 2: Understand the Reaction Mechanism
The reaction involves two main steps:
1. Shaking the compound with NaOH, which can lead to the formation of a stable carbocation if the compound is an alkyl halide or a similar structure.
2. The addition of AgNO₃, which reacts with the halide ion (if released) to form a precipitate.

### Step 3: Analyze Stability of Carbocations
The stability of the carbocation formed after the reaction with NaOH is crucial. More stable carbocations are more likely to form and subsequently release halide ions.
- **Tertiary carbocations** are the most stable due to hyperconjugation and inductive effects.
- **Secondary carbocations** are moderately stable.
- **Primary carbocations** are less stable and often do not form.

### Step 4: Check for Yellow Precipitate Formation
The yellow precipitate is typically indicative of the formation of silver halide (AgX), where X is the halide ion.
- Silver iodide (AgI) is known to produce a yellow precipitate.

### Step 5: Identify the Correct Compound
Now we need to check which of the compounds can form a stable carbocation that can release iodide ions when reacted with NaOH and then with AgNO₃.
- If one of the compounds is an alkyl iodide or has the potential to form a stable carbocation with an iodide leaving group, it is likely to give a yellow precipitate.

### Conclusion
Based on the analysis, if Compound B is a benzyl halide or has a similar structure that allows for resonance stabilization, it is likely to be the correct answer. Therefore, **the second compound (Compound B)** will give a yellow precipitate when treated with NaOH followed by AgNO₃.

### Final Answer
The correct compound that will give a yellow precipitate is **Compound B**.

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