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Through S(N)2 reaction we cannot conv...

Through `S_(N)2` reaction we cannot convert

A

`CH_(3) -CH_(2) -CI " into " CH_(3) CH_(2) - CN`

B

`CH_(3) - underset(CH_(3))underset(|)(CH) - Br ` into
`CH_(3) -underset(CH_(3))underset(|)(CH) -O -overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C ) -CH_(3)`

C

`CH_(3) -underset(CH_(3))underset(|)(CH) -Br` into
`CH_(3) -underset(CH_(3))underset(|)(CH ) - O - overset(O) overset(||)(C ) - CH_(3)`

D

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AI Generated Solution

The correct Answer is:
To determine which compound cannot be converted through an \( S_N2 \) reaction, we need to analyze each option provided in the question. The \( S_N2 \) reaction is a bimolecular nucleophilic substitution reaction where a nucleophile attacks a carbon atom, leading to the displacement of a leaving group. ### Step-by-Step Solution: 1. **Option A: CH₃CH₂Cl to CH₃CH₂CN** - In this case, the nucleophile \( CN^- \) can attack the carbon atom bonded to \( Cl \) in \( CH₃CH₂Cl \). - The \( Cl \) atom acts as a leaving group, and the reaction proceeds smoothly to form \( CH₃CH₂CN \). - Therefore, this conversion **can** occur via an \( S_N2 \) reaction. 2. **Option B: CH₃C(CH₃)CH₂Br to a bulky product** - Here, the structure indicates a tertiary carbon due to the bulky \( C(CH₃) \) group. - The nucleophile (which is bulky, such as \( K^+ \) with \( t-BuO^- \)) will not effectively perform an \( S_N2 \) reaction because it is a poor nucleophile due to steric hindrance. - Instead, it will likely undergo an elimination reaction (E2) rather than substitution. - Therefore, this conversion **cannot** occur via an \( S_N2 \) reaction. 3. **Option C: CH₃CHBrCH₃ to CH₃CHCH₃OC(=O)CH₃** - The nucleophile \( OCOCH₃^- \) can attack the carbon bonded to \( Br \). - The \( Br \) will leave as a leaving group, allowing the formation of the desired product. - This conversion **can** occur via an \( S_N2 \) reaction. 4. **Option D: A compound with bromine, phenyl, deuterium, and hydrogen** - The nucleophile \( CH₃^- \) can attack the carbon bonded to \( Br \). - The \( Br \) will leave, allowing for the formation of a new compound. - This conversion **can** also occur via an \( S_N2 \) reaction. ### Conclusion: The only compound that cannot be converted through an \( S_N2 \) reaction is **Option B**: CH₃C(CH₃)CH₂Br to the bulky product.
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