Suppose that `CH_(3) CH_(2) I` is added to an enthanol solution containing an excess of `EtONa` , EtSNa and NaOH in equimolar amounts . What is the major product that will be isolated from the reaction ?

Options

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Answer

To solve the problem, we need to analyze the reaction of `CH3CH2I` (ethyl iodide) with the nucleophiles present in the ethanol solution, which includes `EtONa` (sodium ethoxide), `EtSNa` (sodium ethyl sulfide), and `NaOH` (sodium hydroxide) in equimolar amounts.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactant is `CH3CH2I`, which is an alkyl halide. The nucleophiles present are:
- `EtO^-` (from `EtONa`)
- `EtS^-` (from `EtSNa`)
- `OH^-` (from `NaOH`)

2. **Determine the Nature of Nucleophiles**:
- `EtO^-` (ethoxide ion) is a strong nucleophile and a good base.
- `EtS^-` (ethyl sulfide ion) is also a strong nucleophile but is less basic than `EtO^-`.
- `OH^-` (hydroxide ion) is a strong nucleophile and a strong base as well.

3. **Evaluate Nucleophilicity**:
Among the nucleophiles, `EtS^-` is less basic than `EtO^-`, which makes it a better nucleophile in this context. This is because the more stable the nucleophile, the less likely it is to attack. Since `EtO^-` is more stable due to the electronegativity of oxygen, it will be less reactive compared to `EtS^-`.

4. **Reaction Mechanism**:
The reaction will proceed via a nucleophilic substitution mechanism (likely SN2) where the nucleophile attacks the carbon atom bonded to the iodine atom, leading to the displacement of the iodine atom.

5. **Identify the Major Product**:
Given that `EtS^-` is the best nucleophile in this scenario, it will attack `CH3CH2I`, resulting in the formation of `CH3CH2S^Et` (ethyl sulfide) as the major product.

6. **Final Product**:
The major product isolated from the reaction will be `CH3CH2S^Et` (ethyl sulfide).

### Conclusion:
The major product that will be isolated from the reaction is `CH3CH2S^Et` (ethyl sulfide).