When ethyl chloride reacts with ethanolic sodium nitrite products formed are

Options

A. Ethylnitrite
B. Nitroethane
C. Ethanol
D. Diethylether

Answer

To solve the question regarding the reaction of ethyl chloride with ethanolic sodium nitrite, we will analyze the reaction step by step.

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Ethyl chloride (C2H5Cl)
- Sodium nitrite (NaNO2) in ethanolic solution (C2H5OH)

### Step 2: Understand the Mechanism of Reaction
When ethyl chloride reacts with sodium nitrite, we need to consider the mechanism of nucleophilic substitution. In this case, the chlorine atom in ethyl chloride is a good leaving group.

### Step 3: Nucleophilic Attack
1. The chlorine atom (Cl) in ethyl chloride (C2H5Cl) is more electronegative than carbon, which creates a partial positive charge on the carbon atom.
2. The nitrite ion (NO2^-) from sodium nitrite acts as a nucleophile. The sodium ion (Na+) does not participate in the reaction and remains as a spectator ion.
3. The nitrite ion attacks the electron-deficient carbon atom in ethyl chloride, leading to the departure of the chloride ion.

### Step 4: Formation of Nitroethane
The product formed from this reaction is nitroethane (C2H5NO2). The reaction can be summarized as:
\[ \text{C2H5Cl} + \text{NaNO2} \rightarrow \text{C2H5NO2} + \text{NaCl} \]

### Step 5: Reaction with Ethanol
Now, if ethyl chloride reacts with ethanol (C2H5OH), the mechanism is slightly different:
1. The oxygen atom in ethanol has a lone pair of electrons and can act as a nucleophile.
2. The nucleophilic oxygen attacks the electron-deficient carbon in ethyl chloride, leading to the departure of the chloride ion.

### Step 6: Formation of Diethyl Ether
The product formed in this case is diethyl ether (C2H5OC2H5). The reaction can be summarized as:
\[ \text{C2H5Cl} + \text{C2H5OH} \rightarrow \text{C2H5OC2H5} + \text{HCl} \]

### Conclusion
Thus, when ethyl chloride reacts with ethanolic sodium nitrite, the products formed are:
1. Nitroethane (C2H5NO2)
2. Diethyl ether (C2H5OC2H5)

### Final Answer
The products formed are nitroethane and diethyl ether.

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