STATEMENT 1 : `CH_(3) -O - CH_(2)-Br` is hydrolyzed more readily than `CH_(3) -underset(CI)underset(|)(CH )- CH_(3)`
STATEMENT -2 : Secondary halides are more reactive than primary alkyl halides towards hydrolysis

Answer

To solve the question, we need to analyze both statements and determine their validity based on the principles of organic chemistry, particularly regarding the hydrolysis of haloalkanes.

### Step-by-Step Solution:

1. **Identify the Compounds**:
- The first compound is `CH₃OCH₂Br`, which is a haloether. The bromine is attached to a primary carbon.
- The second compound is `CH₃CHClCH₃`, which is a secondary haloalkane because the chlorine is attached to a carbon that is connected to two other carbons.

**Hint**: Identify the structure and classification of each compound before proceeding.

2. **Understand Hydrolysis Mechanisms**:
- Hydrolysis of haloalkanes can occur through two mechanisms: SN1 and SN2.
- **SN1 Mechanism**: Involves the formation of a carbocation intermediate. This is typical for secondary and tertiary haloalkanes.
- **SN2 Mechanism**: Involves a direct nucleophilic attack on the carbon bearing the halogen, which is typical for primary haloalkanes.

**Hint**: Recall the characteristics of SN1 and SN2 mechanisms and which types of haloalkanes they apply to.

3. **Analyze Statement 1**:
- The statement claims that `CH₃OCH₂Br` is hydrolyzed more readily than `CH₃CHClCH₃`.
- `CH₃OCH₂Br` undergoes hydrolysis via the SN2 mechanism since it is a primary haloalkane.
- `CH₃CHClCH₃` undergoes hydrolysis via the SN1 mechanism as it is a secondary haloalkane, which typically has a higher reactivity due to the stability of the secondary carbocation formed.

**Hint**: Compare the reactivity of primary vs. secondary haloalkanes in hydrolysis.

4. **Evaluate the Reactivity**:
- Secondary haloalkanes (like `CH₃CHClCH₃`) are generally more reactive than primary haloalkanes (like `CH₃OCH₂Br`) because they can form more stable carbocations.
- Therefore, the statement that `CH₃OCH₂Br` is hydrolyzed more readily than `CH₃CHClCH₃` is incorrect.

**Hint**: Consider the stability of carbocations and how that affects the rate of reaction.

5. **Analyze Statement 2**:
- Statement 2 states that secondary halides are more reactive than primary alkyl halides towards hydrolysis.
- This statement is true, as secondary halides can form more stable carbocations compared to primary halides.

**Hint**: Confirm the general trend of reactivity in haloalkanes based on their classification.

6. **Conclusion**:
- Statement 1 is false because `CH₃CHClCH₃` (secondary) is more reactive than `CH₃OCH₂Br` (primary).
- Statement 2 is true as secondary halides are indeed more reactive than primary halides towards hydrolysis.

### Final Answer:
- **Statement 1**: False
- **Statement 2**: True