`CH_(3)CH_(2)NH_(2) overset((CH_(3)CO)_(2)O)underset(Delta) to A+B`, (A) and (B) are

Options

A. `CH_(3)CH_(2)NHCOCH_(2) + CH_(3)CH_(2)N-=C`
B. `CH_(3)CH_(2)NO_(2) + CH_(3)COOH`
C. `CH_(3)CH_(2)NHCOCH_(3)+CH_(3)COOH`
D. `CH_(3)CH_(2)NO_(2)+CH_(3)CH_(2)NHCOCH_(3)`

Answer

To solve the question, we need to analyze the reaction of ethylamine (CH₃CH₂NH₂) with acetic anhydride ((CH₃CO)₂O) upon heating. Let's break down the steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Ethylamine (CH₃CH₂NH₂)
- Acetic anhydride ((CH₃CO)₂O)

### Step 2: Understand the Reaction Mechanism
Acetic anhydride is a reactive compound that can undergo nucleophilic attack. The nitrogen atom in ethylamine has a lone pair of electrons and can act as a nucleophile.

### Step 3: Nucleophilic Attack
When ethylamine is heated with acetic anhydride, the nitrogen atom attacks one of the carbonyl carbon atoms in the anhydride. This leads to the formation of a tetrahedral intermediate.

### Step 4: Formation of Products
1. The tetrahedral intermediate can collapse, leading to the formation of N-ethylacetamide (CH₃CH₂NHCOCH₃).
2. The other product formed from the acetic anhydride is acetic acid (CH₃COOH).

### Step 5: Write the Balanced Equation
The overall reaction can be summarized as:
\[ \text{CH}_3\text{CH}_2\text{NH}_2 + (CH_3CO)_2O \xrightarrow{\Delta} \text{CH}_3\text{CH}_2\text{NHCOCH}_3 + \text{CH}_3\text{COOH} \]

### Step 6: Identify Products A and B
From the reaction, we identify:
- Product A: N-ethylacetamide (CH₃CH₂NHCOCH₃)
- Product B: Acetic acid (CH₃COOH)

### Conclusion
Thus, the products A and B are:
- A: CH₃CH₂NHCOCH₃
- B: CH₃COOH

The correct answer is option C, which states that the products are N-ethylacetamide and acetic acid.

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