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Graphs are very useful to represent a ph...

Graphs are very useful to represent a physical situation. Various quantities can be easily represented on graphs and other quantites can be determined from the graph. For example the slope of velocity-time graph represents instantaneous acceleration. For a motion with constant acceleration slope of velocity-time graph is constant. If acceleration is changing with time, slope with change and thus velocity-time graph will be a non-linear curve. Further the area of velocity-time graph gives displacement.
For the above situation let `t_(1)` be the time of accelerated motion and `t_(2)` be the time or retarded motion, then the correct relation is

A

`a_(1)t_(2)=a_(2)t_(1)`

B

`a_(1)t_(1)=a_(2)t_(2)`

C

`a_(1)t_(1)^(2)=a_(2)t_(2)^(2)`

D

`a_(1)t_(2)^(2)=a_(2)t_(1)^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze the motion of an object under two different phases: accelerated motion and retarded motion. We will use the first equation of motion to derive the relationship between the times of these two phases. ### Step-by-Step Solution: 1. **Define the Variables**: - Let \( t_1 \) be the time of accelerated motion. - Let \( t_2 \) be the time of retarded motion. - Let \( a_1 \) be the acceleration during the accelerated motion. - Let \( a_2 \) be the retardation (negative acceleration) during the retarded motion. - Let \( V_0 \) be the maximum velocity reached after the accelerated motion. 2. **Apply the First Equation of Motion for Accelerated Motion**: - The first equation of motion states: \[ V = u + at \] - For the accelerated motion, the initial velocity \( u = 0 \) (starting from rest), so: \[ V_0 = 0 + a_1 t_1 \] - This simplifies to: \[ V_0 = a_1 t_1 \quad \text{(Equation 1)} \] 3. **Apply the First Equation of Motion for Retarded Motion**: - In the retarded motion, the initial velocity is \( V_0 \) and the final velocity is \( 0 \) (the object comes to rest). Thus, we have: \[ 0 = V_0 - a_2 t_2 \] - Rearranging gives: \[ V_0 = a_2 t_2 \quad \text{(Equation 2)} \] 4. **Equate the Two Equations**: - Since both equations equal \( V_0 \), we can set them equal to each other: \[ a_1 t_1 = a_2 t_2 \] 5. **Final Relation**: - The final relation between the acceleration during the accelerated motion and the retardation during the retarded motion, along with their respective times, is: \[ a_1 t_1 = a_2 t_2 \] 6. **Conclusion**: - The correct relation between the times of accelerated motion and retarded motion is given by the equation derived above.
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AAKASH INSTITUTE ENGLISH-MOTION IN STRAIGHT LINE-Assignment (SECTION - D)
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