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Graphs are very useful to represent a physical situation. Various quantities can be easily represented on graphs and other quantites can be determined from the graph. For example the slope of velocity-time graph represents instantaneous acceleration. For a motion with constant acceleration slope of velocity-time graph is constant. If acceleration is changing with time, slope will change and thus velocity-time graph will be a non-linear curve. Further the area of velocity-time graph gives displacement.
The correct relation between `v_(0),a_(1),a_(2) and t_(0)` is

A

`v_(0)=((a_(1)a_(2))/(a_(1)+a_(2)))t_(0)^(2)`

B

`v_(0)=((a_(1)a_(2))/(a_(1)+a_(2)))t_(0)`

C

`v_(0)=((a_(1)+a_(2))/(2))t_(0)`

D

`v_(0)=sqrt(a_(1)a_(2)t_(0))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the correct relation between \( V_0 \), \( A_1 \), \( A_2 \), and \( T_0 \), we can analyze the velocity-time graph and the corresponding accelerations. ### Step-by-Step Solution: 1. **Understanding the Graphs**: - We have a velocity-time graph where the velocity increases initially and then decreases. - The initial velocity at time \( t = 0 \) is \( V_0 \). - The slope of the velocity-time graph gives us the acceleration. 2. **Identifying Accelerations**: - When the velocity is increasing, the acceleration is \( A_1 \). - When the velocity is decreasing, the acceleration is \( A_2 \). - The relation for acceleration can be expressed as: \[ A_1 = \frac{V_0}{T_0} \quad \text{(1)} \] \[ A_2 = \frac{V_0}{T_1} \quad \text{(2)} \] where \( T_0 \) is the time for which the velocity is increasing, and \( T_1 \) is the time for which the velocity is decreasing until it becomes zero. 3. **Total Time**: - The total time \( T \) for the motion is given by: \[ T = T_0 + T_1 \quad \text{(3)} \] 4. **Expressing \( T_1 \)**: - From equation (2), we can express \( T_1 \) as: \[ T_1 = \frac{V_0}{A_2} \quad \text{(4)} \] 5. **Substituting \( T_1 \) in Total Time**: - Substitute equation (4) into equation (3): \[ T = T_0 + \frac{V_0}{A_2} \] 6. **Substituting \( T_0 \)**: - From equation (1), we can express \( T_0 \) as: \[ T_0 = \frac{V_0}{A_1} \quad \text{(5)} \] - Substitute equation (5) into the total time equation: \[ T = \frac{V_0}{A_1} + \frac{V_0}{A_2} \] 7. **Finding a Common Denominator**: - Combine the fractions: \[ T = V_0 \left( \frac{1}{A_1} + \frac{1}{A_2} \right) = V_0 \cdot \frac{A_1 + A_2}{A_1 A_2} \] 8. **Rearranging for \( V_0 \)**: - Rearranging gives us: \[ V_0 = T \cdot \frac{A_1 A_2}{A_1 + A_2} \] ### Final Relation: Thus, the correct relation between \( V_0 \), \( A_1 \), \( A_2 \), and \( T \) is: \[ V_0 = T \cdot \frac{A_1 A_2}{A_1 + A_2} \]
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Graphs are very useful to represent a physical situation. Various quantities can be easily represented on graphs and other quantites can be determined from the graph. For example the slope of velocity-time graph represents instantaneous acceleration. For a motion with constant acceleration slope of velocity-time graph is constant. If acceleration is changing with time, slope will change and thus velocity-time graph will be a non-linear curve. Further the area of velocity-time graph gives displacement. For the given velocity-time graph the possibly correct acceleration-time relationship is

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AAKASH INSTITUTE ENGLISH-MOTION IN STRAIGHT LINE-Assignment (SECTION - D)
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