A ball of mass 1 kg is projected with `10ms^(-1)` froom the top of a toer of height 20 m. What is its speed when it is at vertical distance of 10 m below point of projection? `(g=10ms^(-2))`

Explanation

To solve the problem, we will use the work-energy theorem, which states that the work done by all forces acting on an object is equal to the change in its kinetic energy.

### Step-by-Step Solution:

1. **Identify the Given Data:**
- Mass of the ball, \( m = 1 \, \text{kg} \)
- Initial speed of the ball, \( u = 10 \, \text{m/s} \)
- Height of the tower, \( h = 20 \, \text{m} \)
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