A bullet of mass 200 g hits a block of thickness 6 cm with a speed of `100ms^(-1).` It emerges with `10%` of its initial KE. Find its emergent speed

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Identify the given data
- Mass of the bullet, \( m = 200 \, \text{g} = 0.2 \, \text{kg} \) (convert grams to kilograms)
- Initial speed of the bullet, \( u = 100 \, \text{m/s} \)
- The bullet emerges with \( 10\% \) of its initial kinetic energy.

### Step 2: Calculate the initial kinetic energy (KE_initial)
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