A particle moves along x-axis from `x=0` to `x=2` m under the influence of a force F (in N) given by `F=3x^(2)+2x-5.` Calculate the work done

Explanation

To calculate the work done by the force \( F = 3x^2 + 2x - 5 \) as a particle moves from \( x = 0 \) m to \( x = 2 \) m, we will use the work integral for variable forces. The work done \( W \) is given by the integral of the force over the displacement:

\[ W = \int_{x_1}^{x_2} F \, dx \]

### Step 1: Set up the integral
We need to evaluate the integral of the force function from \( x = 0 \) to \( x = 2 \):
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