A 10 metric ton truck drives up a hilly road of gradient 1 in 50 at a speed of `36kmh^(-1)` if the co-efficient of kinetic friction between the road and tyres is 0.2, calculate the power delivered by the engine `(g=10ms^(-2))`

Explanation

To solve the problem, we need to calculate the power delivered by the engine of a truck driving up a hilly road. Here’s a step-by-step solution:

### Step 1: Convert the mass of the truck to kilograms
The mass of the truck is given as 10 metric tons.
1 metric ton = 1000 kg, therefore:
\[ \text{Mass of the truck} = 10 \times 1000 \, \text{kg} = 10,000 \, \text{kg} = 10^4 \, \text{kg} \]
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