A bullet of mass 20 g travelling horizontally at `100 ms^(-1)` gets embedded at the centre of a block of wood of mass 1kg, suspended by a light vertical string of 1m in length. Calculate the maximum inclination of the string to the vertical.

Explanation

To solve the problem step by step, we will use the principles of conservation of momentum and conservation of energy.

### Step 1: Conservation of Momentum
The bullet of mass \( m_1 = 20 \, \text{g} = 0.02 \, \text{kg} \) is traveling horizontally at a velocity \( v_1 = 100 \, \text{m/s} \). The block of wood has a mass \( m_2 = 1 \, \text{kg} \) and is initially at rest (\( v_2 = 0 \, \text{m/s} \)).

Using the conservation of momentum:
\[
m_1 v_1 + m_2 v_2 = (m_1 + m_2) v
...