For a freely falling body

Options

A. True weight = Apparent weight
B. True weight lt Apparent weight
C. Apparent weight is zero
D. Apparent weight gt Normal reaction

Answer

To solve the question regarding a freely falling body, we need to analyze the forces acting on the body and understand the concept of apparent weight.

### Step-by-Step Solution:

1. **Understanding the Forces**:
- When an object of mass \( m \) is in a gravitational field, it experiences a gravitational force (true weight) given by \( W = mg \), where \( g \) is the acceleration due to gravity.

2. **Normal Force in a Non-Free Falling Situation**:
- In a stationary situation or when the object is not falling, the normal force \( N \) acting on the object balances the gravitational force. Thus, we have:
\[ N = mg \]
- Here, the object feels its full weight.

3. **Free Fall Condition**:
- When the object is in free fall, it accelerates downwards at the same rate as gravity, which means its acceleration \( a = g \).

4. **Applying Newton's Second Law**:
- In a free-falling scenario, we can apply Newton's second law. The net force acting on the object is:
\[ F_{\text{net}} = mg - N \]
- Since the object is in free fall, the net force is also equal to \( ma \). Therefore, we can write:
\[ mg - N = ma \]

5. **Substituting for Free Fall**:
- In free fall, the acceleration \( a \) is equal to \( g \). Thus, we substitute \( a \) with \( g \):
\[ mg - N = mg \]

6. **Solving for Normal Force**:
- Rearranging the equation gives:
\[ N = mg - mg = 0 \]
- This indicates that the normal force (apparent weight) acting on the object is zero during free fall.

7. **Conclusion**:
- Therefore, the apparent weight of the object in free fall is zero.

### Final Answer:
The correct option is that the apparent weight is zero.

---