For Question , find maximum velocity and maximum acceleration
Hint `:` Maximum velocity `= Aomega`
Maximum acceleration`= A omega^(2)`

A particle executes SHM on a straight line path. The amplitude of oscillation is 3cm . magnitude of its acceleration is equal to that of its velocity when its displacement from the mean position is 1cm.

Explanation

To solve the problem step by step, we will follow the given hints and the information provided in the question.

### Step 1: Identify the Given Values
- Amplitude \( A = 3 \, \text{cm} \)
- Displacement from the mean position \( x = 1 \, \text{cm} \)

### Step 2: Use the Relationship Between Velocity and Acceleration
The problem states that the magnitude of acceleration is equal to that of velocity when the displacement is \( 1 \, \text{cm} \).
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