The acceleration of a particle performing SHM is`12 cm //s^(2)` at a distance of 3 cm from the mean position . Calculate its time - period .
Hint `: a = omega^(2) x`
`a = 12 cm//s^(2) , x=3cm`
Find `omega`
`T= (pi)/(omega)`

Explanation

To solve the problem, we will follow the steps outlined in the hint and the video transcript.

### Step 1: Understand the relationship between acceleration, angular frequency, and displacement
In simple harmonic motion (SHM), the acceleration \( a \) of a particle is given by the formula:
\[ a = \omega^2 x \]
where:
...