If force constant = 100 N/m, find the potential energy of the block at 0.05 m from the mean position
Hint `: P.E. = (1)/(2) kx^(2)`

Explanation

To find the potential energy of the block at a distance of 0.05 m from the mean position, we can use the formula for potential energy in a spring system:

**Step 1: Write down the formula for potential energy (P.E.)**
The potential energy (P.E.) stored in a spring is given by the formula:
\[ P.E. = \frac{1}{2} k x^2 \]
where \( k \) is the force constant (spring constant) and \( x \) is the displacement from the mean position.
...