What will be the time period of a pendulum which beats seconds ( i.e.,it passes through the mean position after every one second ) it its length is doubled ?
Hint `: T = 2pi sqrt((L)/(g))=2` ....(i)
`T' = 2pi sqrt((2L)/(g)) `
Fin `T'` using equation (i)

Explanation

To find the time period of a pendulum when its length is doubled, we can follow these steps:

### Step 1: Understand the formula for the time period of a simple pendulum
The time period \( T \) of a simple pendulum is given by the formula:
\[ T = 2\pi \sqrt{\frac{L}{g}} \]
where:
...