A simple pendulum with a metallic bob has a time period T.The bob is now immersed in a non-viscous liquid and oscillated . If the density of the liuid is `(1)/(4)` that of metal , what will be the time period of the same pendulum?
Hint `:` If the solid bob of the pendulum has relative densty D and has been submerged in a non-viscous liquid of relative density `rho` then effective acceleration due to gravity `g' = g-(g)/(n) ` where `n = (D)/( rho)`

Explanation

To solve the problem step by step, we will follow the hints and the information provided in the question.

### Step 1: Understand the Time Period of a Simple Pendulum
The time period \( T \) of a simple pendulum is given by the formula:
\[ T = 2\pi \sqrt{\frac{L}{g}} \]
where \( L \) is the length of the pendulum and \( g \) is the acceleration due to gravity.
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