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Radon has 3.8 days as its half-life . Ho...

Radon has 3.8 days as its half-life . How much radon will be left out of 15 mg mass after 38 days ?

Text Solution

Verified by Experts

The number of half-lives in 38 days is given by `n=38/3.8`=10
`N=N_0(1/2)^n`
`N=15(1/2)^10`
Solving we get, N=0.014 mg
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