A deutron strikes `._8 O^16` nucleus with subsequent emission of an alpha particle. Idenify the nucleus so produced.

Explanation

To solve the problem of identifying the nucleus produced when a deuteron strikes an oxygen-16 nucleus with the subsequent emission of an alpha particle, we can follow these steps:

### Step 1: Write the equation for the reaction
We start by identifying the particles involved in the reaction. The deuteron is represented as \( \, ^2_1H \) (with a mass number of 2 and an atomic number of 1), and the oxygen-16 nucleus is represented as \( \, ^{16}_8O \) (with a mass number of 16 and an atomic number of 8). The reaction can be expressed as:

\[ ^2_1H + ^{16}_8O \rightarrow X + ^4_2He \]
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