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Calculate the energy released in the fol...

Calculate the energy released in the following reaction
`._3Li^6 + ._0n^1 to ._2He^4 + ._1H^3`

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To calculate the energy released in the reaction \( _3Li^6 + _0n^1 \to _2He^4 + _1H^3 \), we will follow these steps: ### Step 1: Identify the masses of the reactants and products - **Reactants:** - Mass of Lithium-6 (\( _3Li^6 \)): \( 6.015126 \, u \) - Mass of Neutron (\( _0n^1 \)): \( 1.008665 \, u \) ...
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