Obtain the approximate value of the radius of (a)a nucleus of `._2^4He`
(b)a nucleus of `._92^238U`
(c )What is the ratio of these radii ?

Answer

(a)`1.9xx10^(-15)` m
(b)`7.4xx10^(-15)`m
(c )3.90 :1

Explanation

`R=R_0A^(1//3) , (R_0=1.2xx10^(-15) m)`
(a)For `._2^4He` nucleus , A=4
(b)For `._92^238U`, A=238
(c ) Ratio =`a/b`