Home
Class 12
MATHS
The area bounded by curve |x|+|y| >= 1 a...

The area bounded by curve `|x|+|y| >= 1 and x^2+y^2 <= 1` for `x >= 0` is

A

`2` sq. units

B

`(pi)/(2)` sq. units

C

`((pi-2))/(2)` sq. units

D

`(pi - 2)` sq. units

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF INTEGRALS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section - C Objective Type Questions (More than one options are correct)|3 Videos
  • APPLICATION OF INTEGRALS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section - D Linked Comprehension Type Questions|3 Videos
  • APPLICATION OF INTEGRALS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section - A Competition Level Questions|24 Videos
  • APPLICATION OF DERIVATIVES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment SECTION-J (Aakash Challengers Questions )|8 Videos
  • BINOMIAL THEOREM

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (section-J) Objective type question (Aakash Challengers Questions)|4 Videos

Similar Questions

Explore conceptually related problems

Find the area bounded by curves (x-1)^2+y^2=1 and x^2+y^2=1 .

Find the area bounded by the curves x+2|y|=1 and x=0 .

Find the area bounded by the curves x+2|y|=1 and x=0 .

The area bounded by the curves y = |x| - 1 and y = -|x| +1 is equal to

Find the area bounded by curve y = x^(2) - 1 and y = 1 .

The area bounded by the curve y=3/|x| and y+|2-x|=2 is

The area bounded between curves y^2 = x and y= |x|

Find the area bounded by the curves x^2 = y , x^2 = -y and y^2 = 4x -3

The area bounded by the curves x+y=2 and y=x^2 above x-axis in the first quadrant is ,

The area bounded by the curves x=y^(2) and x=3-2y^(2) is