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mean deviation about median for the foll...

mean deviation about median for the following data 2,5,7,2,4,6,10,12,5

A

2.4

B

3

C

1.9

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the mean deviation about the median for the given data set \(2, 5, 7, 2, 4, 6, 10, 12, 5\), we will follow these steps: ### Step 1: Organize the Data First, we need to arrange the data in ascending order. **Data in ascending order:** \[2, 2, 4, 5, 5, 6, 7, 10, 12\] ### Step 2: Create a Frequency Distribution Table Next, we will create a frequency distribution table. | \(x_i\) | Frequency (\(f_i\)) | |---------|---------------------| | 2 | 2 | | 4 | 1 | | 5 | 2 | | 6 | 1 | | 7 | 1 | | 10 | 1 | | 12 | 1 | ### Step 3: Calculate Cumulative Frequency Now, we calculate the cumulative frequency. | \(x_i\) | Frequency (\(f_i\)) | Cumulative Frequency (\(cf\)) | |---------|---------------------|-------------------------------| | 2 | 2 | 2 | | 4 | 1 | 3 | | 5 | 2 | 5 | | 6 | 1 | 6 | | 7 | 1 | 7 | | 10 | 1 | 8 | | 12 | 1 | 9 | ### Step 4: Find the Median To find the median, we need to find \( \frac{N}{2} \) where \( N \) is the total number of observations. Here, \( N = 9 \), so \( \frac{N}{2} = 4.5 \). Looking at the cumulative frequency, the median is the value corresponding to the cumulative frequency just greater than \( 4.5 \), which is \( 5 \). Thus, the median is: **Median = 5** ### Step 5: Calculate Deviations from the Median Now, we calculate the absolute deviations from the median. \[ \text{Deviation} = |x_i - \text{Median}| \] | \(x_i\) | Deviation (\(|x_i - 5|\)) | |---------|---------------------------| | 2 | 3 | | 2 | 3 | | 4 | 1 | | 5 | 0 | | 5 | 0 | | 6 | 1 | | 7 | 2 | | 10 | 5 | | 12 | 7 | ### Step 6: Calculate \( f_i \cdot d_i \) Now, we multiply each deviation by its corresponding frequency. | \(x_i\) | Frequency (\(f_i\)) | Deviation (\(|x_i - 5|\)) | \(f_i \cdot d_i\) | |---------|---------------------|---------------------------|--------------------| | 2 | 2 | 3 | 6 | | 4 | 1 | 1 | 1 | | 5 | 2 | 0 | 0 | | 6 | 1 | 1 | 1 | | 7 | 1 | 2 | 2 | | 10 | 1 | 5 | 5 | | 12 | 1 | 7 | 7 | ### Step 7: Sum of \( f_i \cdot d_i \) and \( f_i \) Now, we calculate the total of \( f_i \cdot d_i \) and \( f_i \). \[ \sum f_i \cdot d_i = 6 + 1 + 0 + 1 + 2 + 5 + 7 = 22 \] \[ \sum f_i = 9 \] ### Step 8: Calculate Mean Deviation Finally, we calculate the mean deviation about the median using the formula: \[ \text{Mean Deviation} = \frac{\sum f_i \cdot d_i}{\sum f_i} = \frac{22}{9} \approx 2.44 \] ### Final Answer The mean deviation about the median is approximately **2.44**. ---
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