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Coefficients of variation of two distrib...

Coefficients of variation of two distribution are 15 and 20 and their means are 20 and 10 respectively. If their standard deviations are `sigma_1` and `sigma_2` then

A

`3sigma_1=2sigma_2`

B

`sigma_1 lt sigma_2`

C

`2sigma_1 =3sigma_2`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the relationship between the standard deviations \( \sigma_1 \) and \( \sigma_2 \) of two distributions given their coefficients of variation and means. ### Step-by-Step Solution: 1. **Understand the Coefficient of Variation (CV)**: The coefficient of variation is defined as: \[ CV = \frac{\sigma}{\text{mean}} \times 100 \] where \( \sigma \) is the standard deviation and mean is the average of the distribution. 2. **Set Up Equations for Each Distribution**: For the first distribution: \[ CV_1 = \frac{\sigma_1}{\text{mean}_1} \times 100 \] Given \( CV_1 = 15 \) and \( \text{mean}_1 = 20 \): \[ 15 = \frac{\sigma_1}{20} \times 100 \] Rearranging gives: \[ \sigma_1 = \frac{15 \times 20}{100} = 3 \] For the second distribution: \[ CV_2 = \frac{\sigma_2}{\text{mean}_2} \times 100 \] Given \( CV_2 = 20 \) and \( \text{mean}_2 = 10 \): \[ 20 = \frac{\sigma_2}{10} \times 100 \] Rearranging gives: \[ \sigma_2 = \frac{20 \times 10}{100} = 2 \] 3. **Establish the Relationship Between \( \sigma_1 \) and \( \sigma_2 \)**: Now we have: \[ \sigma_1 = 3 \quad \text{and} \quad \sigma_2 = 2 \] To find the relationship, we can express it as: \[ \frac{\sigma_1}{\sigma_2} = \frac{3}{2} \] This can be rearranged to: \[ 2\sigma_1 = 3\sigma_2 \] 4. **Final Relation**: Thus, the relationship between the standard deviations is: \[ 2\sigma_1 = 3\sigma_2 \] ### Conclusion: The relationship derived from the coefficients of variation and means is: \[ 2\sigma_1 = 3\sigma_2 \]
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