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The number of ways in which 20 girls be ...

The number of ways in which 20 girls be seated round a table if there are only 10 chairs

A

`(""^(20)C_(10))/(2)`

B

`""^(20)C_(10)9!`

C

`(""^(20)C_(10))/(10)`

D

`(""^(20)P_(10))/(10)`

Text Solution

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The correct Answer is:
To solve the problem of seating 20 girls around a round table with only 10 chairs, we can follow these steps: ### Step-by-Step Solution: 1. **Select 10 Girls from 20:** We first need to choose 10 girls out of the 20 available. The number of ways to choose 10 girls from 20 is given by the combination formula: \[ \binom{20}{10} \] 2. **Arrange the Selected Girls:** After selecting the 10 girls, we need to arrange them in the 10 chairs around the round table. The arrangement of \( n \) objects in a circle is given by \( (n-1)! \). Therefore, for 10 girls, the number of arrangements is: \[ (10 - 1)! = 9! \] 3. **Total Ways to Seat the Girls:** The total number of ways to seat the girls is the product of the number of ways to choose the girls and the number of ways to arrange them: \[ \text{Total Ways} = \binom{20}{10} \times 9! \] 4. **Calculating the Combination:** We can express the combination \( \binom{20}{10} \) using factorials: \[ \binom{20}{10} = \frac{20!}{10! \times 10!} \] 5. **Final Expression:** Substituting this back into our total ways expression, we get: \[ \text{Total Ways} = \frac{20!}{10! \times 10!} \times 9! \] 6. **Simplifying the Expression:** We can simplify this further: \[ \text{Total Ways} = \frac{20! \times 9!}{10! \times 10!} \] 7. **Understanding the Result:** This expression can also be interpreted as: \[ \text{Total Ways} = \frac{20P10}{10} \] where \( 20P10 \) is the number of permutations of 20 items taken 10 at a time. ### Final Answer: Thus, the total number of ways to seat 20 girls in 10 chairs around a round table is: \[ \text{Total Ways} = \binom{20}{10} \times 9! \]
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