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The number of ways in which 5 distinct t...

The number of ways in which 5 distinct toys can be distributed among 8 children is

A

`2^(15)`

B

`8^(5)`

C

`5^(8)`

D

`32768`

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The correct Answer is:
To solve the problem of distributing 5 distinct toys among 8 children, we can follow these steps: ### Step-by-step Solution: 1. **Identify the number of toys and children**: - We have 5 distinct toys (let's denote them as T1, T2, T3, T4, T5). - We have 8 distinct children (let's denote them as C1, C2, C3, C4, C5, C6, C7, C8). 2. **Determine the distribution options for each toy**: - For each toy, we can choose any one of the 8 children to give the toy to. - This means that for the first toy (T1), there are 8 possible choices (C1 to C8). - The same applies for the second toy (T2), third toy (T3), fourth toy (T4), and fifth toy (T5). 3. **Calculate the total number of ways to distribute the toys**: - Since each toy can be given to any of the 8 children independently, we multiply the number of choices for each toy. - Therefore, the total number of ways to distribute the toys is: \[ \text{Total ways} = 8 \times 8 \times 8 \times 8 \times 8 = 8^5 \] 4. **Final calculation**: - We can compute \(8^5\): \[ 8^5 = 32768 \] 5. **Conclusion**: - The number of ways in which 5 distinct toys can be distributed among 8 children is \(8^5\) or 32768.
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