The number of ordered triplets of positive integers which satisfy the inequality `20 le x. + y + z le 50` is p, then `(p - 631)/(100)` is equal to _______ .

Explanation

To solve the problem of finding the number of ordered triplets of positive integers \((x, y, z)\) that satisfy the inequality \(20 \leq x + y + z \leq 50\), we can follow these steps:

### Step 1: Understand the Problem
We need to find the number of ordered triplets \((x, y, z)\) such that their sum lies between 20 and 50. This means we need to consider two cases: when \(x + y + z = n\) for \(n\) ranging from 20 to 50.

### Step 2: Use the Stars and Bars Method
For any integer \(n\), the number of ordered triplets of positive integers that sum to \(n\) can be found using the formula:
\[
...