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If |(x^2+x,x+1,x-2),(2x^2+3x-1,3x,3x-3)...

If `|(x^2+x,x+1,x-2),(2x^2+3x-1,3x,3x-3),(x^2+2x+3,2x-1,2x-1)|=ax-12` then 'a' is equal to (1) 12 (2) 24 (3) -12 (4) -24

A

`A+B=12`

B

`A-B=36`

C

`A^2+B^2=720`

D

`A+2B=0`

Text Solution

AI Generated Solution

To solve the determinant problem step by step, we will evaluate the determinant and find the value of 'a' such that the determinant equals \( ax - 12 \). ### Step 1: Write the Determinant We start with the determinant given in the question: \[ D = \begin{vmatrix} x^2 + x & x + 1 & x - 2 \\ 2x^2 + 3x - 1 & 3x & 3x - 3 \\ ...
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