Find the centre and radius of the circle `x^(2) + y^(2) + 6x -10y -2 =0`

Explanation

To find the center and radius of the circle given by the equation \( x^2 + y^2 + 6x - 10y - 2 = 0 \), we can follow these steps:

### Step 1: Rewrite the equation in standard form
The general equation of a circle is given by:
\[ x^2 + y^2 + 2gx + 2fy + c = 0 \]
We need to compare our equation with this general form. The given equation is:
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