Find the center and radius of the circle given by the equation `2x^2+2y^2+3x+4y+9/8=0.`

Answer

The co-ordinates of the centre are `(-(3)/(4), -1)` and radius `= sqrt(((3)/(4))^(2) _ (1)^(2) - (9)/(16)) =1`

Explanation

[Hint : Make the coefficient of `x^(2) and y^(2)` unity and then compare witht the general equation or the circle ]