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Find the derivative of f(x)= xsin x from...

Find the derivative of `f(x)= xsin x` from the first principle.

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To find the derivative of the function \( f(x) = x \sin x \) using the first principle of derivatives, we will follow these steps: ### Step 1: Write the definition of the derivative The derivative of \( f(x) \) from the first principle is given by: \[ f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \] ### Step 2: Calculate \( f(x+h) \) Substituting \( x + h \) into the function: \[ f(x+h) = (x+h) \sin(x+h) \] ### Step 3: Substitute \( f(x+h) \) and \( f(x) \) into the derivative formula Now we substitute \( f(x+h) \) and \( f(x) \) into the derivative formula: \[ f'(x) = \lim_{h \to 0} \frac{(x+h) \sin(x+h) - x \sin x}{h} \] ### Step 4: Expand \( (x+h) \sin(x+h) \) Using the angle addition formula for sine, we can expand \( \sin(x+h) \): \[ \sin(x+h) = \sin x \cos h + \cos x \sin h \] Thus, \[ f(x+h) = (x+h)(\sin x \cos h + \cos x \sin h) \] Expanding this gives: \[ f(x+h) = x \sin x \cos h + x \cos x \sin h + h \sin x \cos h + h \cos x \sin h \] ### Step 5: Substitute back into the limit expression Now substituting back into our limit: \[ f'(x) = \lim_{h \to 0} \frac{x \sin x \cos h + x \cos x \sin h + h \sin x \cos h + h \cos x \sin h - x \sin x}{h} \] ### Step 6: Simplify the expression This simplifies to: \[ f'(x) = \lim_{h \to 0} \frac{x \sin x (\cos h - 1) + x \cos x \sin h + h \sin x \cos h + h \cos x \sin h}{h} \] ### Step 7: Split the limit into parts We can split the limit into separate terms: \[ f'(x) = \lim_{h \to 0} \left( \frac{x \sin x (\cos h - 1)}{h} + \frac{x \cos x \sin h}{h} + \sin x \cos h + \cos x \sin h \right) \] ### Step 8: Evaluate the limits 1. As \( h \to 0 \), \( \cos h \to 1 \) and \( \sin h \to h \), thus: - \( \frac{x \sin x (\cos h - 1)}{h} \to 0 \) - \( \frac{x \cos x \sin h}{h} \to x \cos x \) - \( \sin x \cos h \to \sin x \) - \( \cos x \sin h \to 0 \) Putting it all together: \[ f'(x) = 0 + x \cos x + \sin x + 0 = x \cos x + \sin x \] ### Final Result Thus, the derivative of \( f(x) = x \sin x \) is: \[ f'(x) = x \cos x + \sin x \]
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