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lim(x to 0) (x^(4) + x^(2) - 2x + 1) is ...

`lim_(x to 0) (x^(4) + x^(2) - 2x + 1)` is eqal to

A

0

B

1

C

2

D

`-1`

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The correct Answer is:
To solve the limit \( \lim_{x \to 0} (x^4 + x^2 - 2x + 1) \), we will evaluate the expression by substituting \( x \) with \( 0 \). ### Step-by-Step Solution: 1. **Substitute \( x = 0 \)**: \[ x^4 + x^2 - 2x + 1 \quad \text{becomes} \quad 0^4 + 0^2 - 2(0) + 1 \] 2. **Calculate each term**: - \( 0^4 = 0 \) - \( 0^2 = 0 \) - \( -2(0) = 0 \) - The constant term is \( 1 \) 3. **Combine the results**: \[ 0 + 0 + 0 + 1 = 1 \] 4. **Conclusion**: \[ \lim_{x \to 0} (x^4 + x^2 - 2x + 1) = 1 \] Thus, the limit is equal to \( 1 \).
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AAKASH INSTITUTE ENGLISH-LIMITS AND DERIVATIVES -SECTION - A
  1. lim(x to 0) (x^(4) + x^(2) - 2x + 1) is eqal to

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  2. If the function f (x) = {{:(3,x lt 0),(12, x gt 0):} then lim(x to 0) ...

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  3. lim(x to 3) (3x + 5) is equal to

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  4. lim(x to 2) (x^(2) - 4)/(x + 3) is equal to

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  5. If F (x) = {{:(-x^(2) + 1, x lt 0),(0,x = 0),(x^(2) + 1,x gt = 0):}, ....

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  6. lim(x to 0) (sqrt(1 + 3x) + sqrt(1 - 3x))/(1 + 3x) is equal to

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  7. lim(x to 1) (x^(2) + x - 2)/(x^(2) - 1) is equal to

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  8. underset(x to 3)(lim) (x^(2) - 27)/(x^(2) - 9) is equal to

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  9. lim(x to 1//2) (8x^(3) - 1)/(16 x^(4) - 1) is equal to

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  10. lim(x to 2) (x^(7) - 128)/(x - 2) is equal to

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  11. lim(x to 0) (sin 3x)/(x) is equal to

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  12. lim(x -0) (1 - cos 4x)/(x^(2)) is equal to

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  13. lim(x to 0) ((1 + x)^(5) -1)/((1 + x)^(3) - 1) is equal to

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  14. lim(x to 0) (K sin x)/(lx + mx cos x) is equal to

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  15. lim(x to 0) (sqrt(1 + x + x^(2)) - sqrt(x + 1))/(2X^(2)) is equal to

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  16. lim(x to 0) (sin^(2) x//4)/(x) is equal to

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  17. lim(x to 0) (2 sin x - sin 2x)/(x^(3)) ie equal to

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  18. 'underset(x to 0) (sqrt(a +x) - sqrt(a))/(x sqrt(a^(2) + ax)) is equal...

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  19. Evaluate underset(x to 3)(lim) (x^(3) - 7x^(2) + 15x - 9)/(x^(4) - 5x^...

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  20. If f (x) = x^(4) + 2x^(3), them lim(x to 2) (f(x) - f(2))/(x - 2) is ...

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