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If y=tanxtan2xtan3x, then (dy)/(dx) has ...

If `y=tanxtan2xtan3x,` then `(dy)/(dx)` has the value equal to

A

`3 sec^(2) 3x tan x tan 2x + 2sec^(2) 2x tan 3 x tan x + sec^(2) x tan2 x tan 3x`

B

`2y (cosec 2x + 2 cosec 4x + 3 cosec 6x)`

C

`3 sec^(2) 3 x - 2 sec^(2) 2x - sec^(2) x`

D

`sec^(2) x + 2 sec^(2)2x + 3sec^(2) 3x`

Text Solution

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The correct Answer is:
A, B, C
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