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The volume of a spherical balloon is inc...

The volume of a spherical balloon is increasing at the rate of 20 `cm^3`/`sec` . Find the rate of change of its surface area at the instant when radius is 5 cm.

Text Solution

Verified by Experts

Volume of sphere is given by
`V=(4)/(3)pir^(3)`
Differentiate with respect to time
`(dV)/(dt)=(4)/(3)pi xx 3r^(2)""(dr)/(dt)`
`implies (dV)/(dt)=4pir^(3)""(dr)/(dt)`
`implies (dr)/(dt)=((dV)/(dt))/(4pir^(2))=(20)/(4pixx25)=(1)/(5pi)` cm/ second .
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