Home
Class 12
MATHS
Find the point at which the tangent to t...

Find the point at which the tangent to the curve `y=sqrt(4x-3)-2` is vertical ?

Text Solution

AI Generated Solution

To find the point at which the tangent to the curve \( y = \sqrt{4x - 3} - 2 \) is vertical, we will follow these steps: ### Step 1: Differentiate the function First, we need to find the derivative \( \frac{dy}{dx} \) of the function \( y \). Given: \[ y = \sqrt{4x - 3} - 2 ...
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    AAKASH INSTITUTE ENGLISH|Exercise TRY YOURSELF|39 Videos

  • APPLICATION OF DERIVATIVES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment SECTION-A (Competition Level Questions)|50 Videos

  • APPLICATION OF INTEGRALS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section - I Aakash Challengers Questions|2 Videos

Similar Questions

Explore conceptually related problems

Find the point at which the tangent to the curve y=sqrt(4x-3)-1 has its slope 2/3 .

The point at which the tangent to the curve y=x^2-4x is parallel to x-axis is

Find the equation of the tangent line to the curve y=sqrt(5x-3)-2 which is parallel to the line 4x-2y+3=0

Find the equation of the tangent line to the curve y=sqrt(5x-3)-2 which is parallel to the line 4x-2y+3=0 .

Find the equation of the tangent to the curve y=sqrt(4x-2)\ which is parallel to the line 4x-2y+5=0

Find the equation of the tangent to the curve y=sqrt(3x-2) which is parallel to the line 4x-2y+5=0.

Find the equation of the tangent to the curve y=sqrt(3x-2) which is parallel to the line 4x-2y + 5 =0 .

The point at which the tangent to the curve y = 2 x^(2) - x + 1 is parallel to the line y = 3 x + 9 is

Find the equation of the tangent to the curve y=(x^3-1)(x-2) at the points where the curve cuts the x-axis.

Find the equation of the tangent to the curve y=(x^3-1)(x-2) at the points where the curve cuts the x-axis.