Home
Class 12
MATHS
let f(x)=(x^2-1)^n (x^2+x-1) then f(x) ...

let `f(x)=(x^2-1)^n (x^2+x-1) ` then `f(x)` has local minimum at `x=1` when

A

n=2

B

n=3

C

n=4

D

n=5

Text Solution

Verified by Experts

The correct Answer is:
A, C
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment SECTION-D ( Linked Comprehension Type Questions )|3 Videos

  • APPLICATION OF DERIVATIVES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment SECTION-E ( Assertion -Reason Type Questions )|4 Videos

  • APPLICATION OF DERIVATIVES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment SECTION-C( Objective Type Questions ( More than one option are correct ))|1 Videos

  • APPLICATION OF INTEGRALS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section - I Aakash Challengers Questions|2 Videos

Similar Questions

Explore conceptually related problems

Let f(x)=(x^2-1)^n(x^2+x+1) then f(x) has local extremum at x=1 when (a) n=2 (b) n=3 (c) n=4 (d) n=6

Let f(x) = (x^2 - 1)^(n+1) * (x^2 + x + 1) . Then f(x) has local extremum at x = 1 , when n is (A) n = 2 (B) n = 4 (C) n = 3 (D) n = 5

Let f(x)=(x-1)^4(x-2)^n ,n in Ndot Then f(x) has (a) a maximum at x=1 if n is odd (b) a maximum at x=1 if n is even (c) a minimum at x=1 if n is even (d) a minima at x=2 if n is even

Let f(x)=(x-a)^2+(x-b)^2+(x-c)^2dot Then, f(x) has a minimum at x= (a+b+c)/3 (b) 1/2 (c) 1/8 (d) none of these

The function f(x)=(x^2-4)^n(x^2-x+1),n in N , assumes a local minimum value at x=2. Then find the possible values of n

The function f(x)=(x^2-4)^n(x^2-x+1),n in N , assumes a local minimum value at x=2. Then find the possible values of n

Let f(x)=x-1/2 log (x^(2)+1) . Then f' (x) is :

Let f(x)=(x-2)^2x^n, n in N Then f(x) has a minimum at

The function f(x) = (x)/( 2) + (2)/( x) has a local minimum at

Let the function f(x) be defined as below f(x)=sin^(-1) lambda+x^2 when 0 =1 . f(x) can have a minimum at x=1 then value of lambda is