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If the tangent at P(1,1) on the curve y...

If the tangent at P(1,1) on the curve `y^(2)=x(2-x)^(2)` meets the curve again at A , then the points A is of the form `((3a)/(b),(a)/(2b))` , where ` a^(2)+b^(2)` is

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To solve the problem, we need to find the point A where the tangent at P(1,1) on the curve \( y^2 = x(2-x)^2 \) meets the curve again. We will follow these steps: ### Step 1: Differentiate the curve equation The given curve is: \[ y^2 = x(2-x)^2 \] To find the slope of the tangent, we differentiate both sides with respect to \( x \): ...
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