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The curve y=ax^(3)+bx^(2)+cx is incline...

The curve `y=ax^(3)+bx^(2)+cx` is inclined at `45^(@)` to x-axis at (0,0) but it touches x-axis at (1,0) , then a+b+c+10 is

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To solve the problem step by step, we will analyze the given conditions and derive the necessary equations. ### Step 1: Understand the given curve The curve is given by the equation: \[ y = ax^3 + bx^2 + cx \] ### Step 2: Condition at (0,0) The curve is inclined at \( 45^\circ \) to the x-axis at the point (0,0). This means that the derivative of the curve at this point should equal 1 (since the slope of a line inclined at \( 45^\circ \) is 1). ...
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