Home
Class 12
MATHS
Find the shortest distance between the l...

Find the shortest distance between the lines `l_(1)and l_(1)` whose vector equations are
`vecr=(hati+hatj) + lambda (3hati + 4hatj - 2hatk) …(i)`
and `vecr=(2hati+3hatj) + mu (6hati + 8hatj - 4hatk) …(ii)`

Text Solution

AI Generated Solution

To find the shortest distance between the two lines given by their vector equations, we can follow these steps: ### Step 1: Identify the direction vectors and points on each line The vector equations of the lines are given as: 1. \( \vec{r_1} = \hat{i} + \hat{j} + \lambda(3\hat{i} + 4\hat{j} - 2\hat{k}) \) 2. \( \vec{r_2} = 2\hat{i} + 3\hat{j} + \mu(6\hat{i} + 8\hat{j} - 4\hat{k}) \) From these equations, we can identify: ...
Promotional Banner

Topper's Solved these Questions

  • THREE DIMENSIONAL GEOMETRY

    AAKASH INSTITUTE ENGLISH|Exercise Illustration|4 Videos
  • THREE DIMENSIONAL GEOMETRY

    AAKASH INSTITUTE ENGLISH|Exercise TRY YOURSELF|97 Videos
  • STRAIGHT LINES

    AAKASH INSTITUTE ENGLISH|Exercise SECTION-J (AAKASH CHALLENGERS QUESTIONS)|5 Videos
  • TRIGNOMETRIC FUNCTIONS

    AAKASH INSTITUTE ENGLISH|Exercise Section - J (Akash Challengers Question)|16 Videos

Similar Questions

Explore conceptually related problems

Find the shortest distance between the lines l_(1) and l_(2) whose vector equation are vecr =lambda (2hati+ 3hatj+ 4hatk) and vecr=(2hati+3hatj)+mu(2hati+3hatj+ 4hatk)

Find the shortest distance between the two lines whose vector equations are given by: vecr=hati+2hatj+3hatk+lamda(2hati+3hatj+4hatk) and vecr=2hati+4hatj+5hatk+mu(3hati+4hatj+5hatk)

Find the shortest distance between the lines whose vector equations are vecr=hati(1+2lambda)+hatj(1-lambda)+lambda hatk and vecr=hati(2+3mu)+hatj(1-5 mu)+hatk(2mu-1)

Find the vector equation of the plane in which the lines vecr=hati+hatj+lambda(hati+2hatj-hatk) and vecr=(hati+hatj)+mu(-hati+hatj-2hatk) lie.

Find the vector equation of the plane in which the lines vecr=hati+hatj+lambda(hati+2hatj-hatk) and vecr=(hati+hatj)+mu(-hati+hatj-2hatk) lie.

Find the shortest distance between the two lines whose vector equations are given by: vecr=(1-lamda)hati+(-2lamda -2)hatj+(3-2lamda)hatk and vecr=(1+mu)hati+(2mu-1)hatj-(1+2mu)hatk

The lines with vector equations are, vecr_(1)=3hati+6hatj+lambda(-4hati+3hatj+2hatk) and vecr_(2)=-2hati+7hatj+mu(-4hati+hatj+hatk) are such that :

The lines with vector equations are, vecr_(1)=3hati+6hatj+lambda(-4hati+3hatj+2hatk) and vecr_(2)=-2hati+7hatj+mu(-4hati+hatj+hatk) are such that :

Find the shortest distance between the lines vecr = hati+hatj+lambda(2hati-hatj+hatk) and vecr = (2 hati+hatj-hatk) + mu (3hati-5hatj + 2hatk)

Find the angle between the lines vecr = (hati+hatj)+lambda(3hati+2hatj+6hatk) and vecr = (hati-hatk) + mu(hati+2hatj+2hatk)