Find the vector equation of a plane passing through intersectio of two planes
`vecr cdot (3hati +4hatj + 5hatk)=9 and vecr cdot (2hati - 3hatj +4hatk)=6` and which also passes through the point
(-1, 0, 1).

Explanation

To find the vector equation of a plane passing through the intersection of two given planes and a specific point, we can follow these steps:

### Step 1: Identify the normal vectors and constants from the given planes
The equations of the two planes are:
1. \( \vec{r} \cdot (3\hat{i} + 4\hat{j} + 5\hat{k}) = 9 \)
2. \( \vec{r} \cdot (2\hat{i} - 3\hat{j} + 4\hat{k}) = 6 \)

From these equations, we can identify the normal vectors:
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