Home
Class 12
MATHS
STATEMENT-1 : The points (2, 3, 5), (7, ...

STATEMENT-1 : The points (2, 3, 5), (7, 5, 7) and (-3, 1, 3) are vertices of an equilateral triangle.
and
STATEMENT-2 : The triangle with equal sides is called an equilateral triangle.

A

Statement-1 is True, Statement-2 is true, Statement- is a correct explanation for Statement -1

B

Statement-1 is True, Statement-2 is true, Statement- is NOT a correct explanation for Statement -1

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False, Statement-2 is true

Text Solution

AI Generated Solution

The correct Answer is:
To determine whether the points (2, 3, 5), (7, 5, 7), and (-3, 1, 3) form an equilateral triangle, we will calculate the lengths of the sides of the triangle formed by these points using the distance formula in three-dimensional geometry. ### Step 1: Identify the points Let: - Point A = (2, 3, 5) - Point B = (7, 5, 7) - Point C = (-3, 1, 3) ### Step 2: Use the distance formula The distance \(d\) between two points \((x_1, y_1, z_1)\) and \((x_2, y_2, z_2)\) in three-dimensional space is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \] ### Step 3: Calculate the lengths of the sides #### Length AB Using the points A and B: \[ AB = \sqrt{(7 - 2)^2 + (5 - 3)^2 + (7 - 5)^2} \] \[ = \sqrt{5^2 + 2^2 + 2^2} = \sqrt{25 + 4 + 4} = \sqrt{33} \] #### Length BC Using the points B and C: \[ BC = \sqrt{(7 - (-3))^2 + (5 - 1)^2 + (7 - 3)^2} \] \[ = \sqrt{(7 + 3)^2 + (5 - 1)^2 + (7 - 3)^2} = \sqrt{10^2 + 4^2 + 4^2} \] \[ = \sqrt{100 + 16 + 16} = \sqrt{132} \] #### Length AC Using the points A and C: \[ AC = \sqrt{(-3 - 2)^2 + (1 - 3)^2 + (3 - 5)^2} \] \[ = \sqrt{(-5)^2 + (-2)^2 + (-2)^2} = \sqrt{25 + 4 + 4} = \sqrt{33} \] ### Step 4: Compare the lengths We have: - \(AB = \sqrt{33}\) - \(BC = \sqrt{132}\) - \(AC = \sqrt{33}\) From the calculations, we find that: - \(AB = AC\) - \(BC \neq AB\) and \(BC \neq AC\) ### Conclusion Since not all sides are equal, the triangle formed by the points (2, 3, 5), (7, 5, 7), and (-3, 1, 3) is not an equilateral triangle. Thus, **Statement 1 is false**. **Statement 2 is true** because a triangle with equal sides is indeed called an equilateral triangle. ### Final Answer - Statement 1: False - Statement 2: True ### Options The correct option is **Option 4**: Statement 1 is false, Statement 2 is true. ---
Promotional Banner

Topper's Solved these Questions

  • THREE DIMENSIONAL GEOMETRY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION - F|4 Videos
  • THREE DIMENSIONAL GEOMETRY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION - G|7 Videos
  • THREE DIMENSIONAL GEOMETRY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION - D COMPREHENSION VI|3 Videos
  • STRAIGHT LINES

    AAKASH INSTITUTE ENGLISH|Exercise SECTION-J (AAKASH CHALLENGERS QUESTIONS)|5 Videos
  • TRIGNOMETRIC FUNCTIONS

    AAKASH INSTITUTE ENGLISH|Exercise Section - J (Akash Challengers Question)|16 Videos

Similar Questions

Explore conceptually related problems

Prove that the points (5,3,2),(3,2,5) and (2,5,3) are the vertices of an equilateral triangle.

Prove that the points (a, a), (-a, -a) and (-asqrt(3), asqrt(3)) are the vertices of an equilateral triangle.

If the point (0,0),(2,2sqrt(3)), and (p,q) are the vertices of an equilateral triangle, then (p ,q) is

Prove that the points A(1, 1) , B(-1, -1) and C(sqrt(3), -sqrt(3)) are the vertices of an equilateral triangle.

Prove that points (2,-1,1),(1,-3,-5) and (3,-4,-4) are the vertices of a righat angled triangle.

Show that the points P(7,3) , Q ( 6,3+ sqrt3) and R (5,3) from an equilateral triangles.

The area of an equilateral triangle with side 2sqrt3 cm is

The side of an equilateral triangle is 3.5 cm. Find its perimeter

If z_(1),z_(2),z_(3) be vertices of an equilateral triangle occurig in the anticlockwise sense, then

STATEMENT-1 : The triangle with vertices (1, 3, 5), (2, 4, 6) and (0, 5, 7) must be a right angle triangle. and STATEMENT-2 : If the dot product of two non-zero vectors is zero then they must be perpendicular.