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A rectangular parallelopiped is formed b...

A rectangular parallelopiped is formed by drawing planes through the points `(1,2,5) and (-1,-1,-1)` parallel to the coordinate planes. Find the length of the diagnol of the parallelopiped.

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To find the length of the diagonal of a rectangular parallelepiped formed by drawing planes through the points \( P(1, 2, 5) \) and \( Q(-1, -1, -1) \) parallel to the coordinate planes, we can follow these steps: ### Step 1: Identify the coordinates of the points We have two points: - \( P(1, 2, 5) \) - \( Q(-1, -1, -1) \) ### Step 2: Calculate the lengths of the edges of the parallelepiped The edges of the parallelepiped can be calculated as follows: 1. **Length along the x-axis (PA)**: \[ PA = |x_1 - x_2| = |1 - (-1)| = |1 + 1| = |2| = 2 \] 2. **Length along the y-axis (PC)**: \[ PC = |y_1 - y_2| = |2 - (-1)| = |2 + 1| = |3| = 3 \] 3. **Length along the z-axis (PE)**: \[ PE = |z_1 - z_2| = |5 - (-1)| = |5 + 1| = |6| = 6 \] ### Step 3: Use the formula for the diagonal of the parallelepiped The length of the diagonal \( D \) of a rectangular parallelepiped can be calculated using the formula: \[ D = \sqrt{l^2 + b^2 + h^2} \] where \( l \), \( b \), and \( h \) are the lengths of the edges along the x, y, and z axes respectively. Substituting the values we calculated: - \( l = 2 \) - \( b = 3 \) - \( h = 6 \) We get: \[ D = \sqrt{2^2 + 3^2 + 6^2} \] Calculating this step-by-step: \[ D = \sqrt{4 + 9 + 36} \] \[ D = \sqrt{49} \] \[ D = 7 \] ### Conclusion The length of the diagonal of the parallelepiped is \( 7 \) units. ---
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