Complete the reaction
`Ph-CH=CH-CHO overset(PhMgBr) underset(H_(3)O^(+)) to` Product

Options

A. `Ph-underset(Ph)underset(|)CH-underset(OH)underset(|)CH-CHO`
B. `Ph-underset(Ph)underset(|)CH=CH_(2)-CHO`
C. `Ph-underset(Ph)underset(|)CH-underset(Ph)underset(|)(CH)-CHO`
D. `Ph-underset(Ph)underset(|)CH-CH_(2)-CH_(2)-OH`

Answer

To complete the reaction of `Ph-CH=CH-CHO` with `PhMgBr` followed by `H3O+`, we will follow these steps:

### Step 1: Identify the Reactants
We start with the reactant:
- `Ph-CH=CH-CHO` (which is a phenyl-substituted aldehyde with a double bond).

### Step 2: Understand the Grignard Reagent
The Grignard reagent is `PhMgBr`. In this case, we can represent it as:
- `Ph^-` (the phenyl anion) and `MgBr^+`.

### Step 3: Nucleophilic Attack
The phenyl anion (`Ph^-`) acts as a nucleophile and will attack the carbon atom of the aldehyde group (C=O) in `Ph-CH=CH-CHO`. This is a 1,4-addition reaction:
- The nucleophile attacks the carbon of the carbonyl group, leading to the formation of a new bond.

### Step 4: Forming the Intermediate
After the nucleophilic attack, we can represent the intermediate as:
- `Ph-CH-CH-CHO^-` (the carbonyl oxygen now carries a negative charge).

### Step 5: Addition of Magnesium Bromide
The magnesium bromide (`MgBr^+`) will coordinate with the negatively charged oxygen:
- The structure now is `Ph-CH-CH-CHO^−MgBr^+`.

### Step 6: Acid Hydrolysis
Next, we perform acid hydrolysis using `H3O+`. The negatively charged oxygen will protonate, leading to the formation of an alcohol:
- The intermediate converts to `Ph-CH-CH(OH)-CHO`.

### Step 7: Tautomerization
The product can undergo tautomerization to form an aldehyde:
- The structure rearranges to yield `Ph-CH=CH-CHO` (the original aldehyde with an additional phenyl group).

### Final Product
The final product of the reaction is:
- `Ph-CH=CH-CHO` (with an additional phenyl group).

### Summary of Product
Thus, the final product after the reaction is:
- `Ph-CH=CH-CHO` (with an aldehyde functional group).

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