The compound which is not reduced by `LiAIH_(4)` is

Options

A. Cyclohexanone
B. 2-Methyl-1-butanol
C. Ethyl benzoate
D. `omega`-caprolactam

Answer

To determine which compound is not reduced by Lithium Aluminium Hydride (LiAlH4), we need to analyze the reducing capabilities of LiAlH4 and the structures of the given compounds.

### Step-by-Step Solution:

1. **Understand the Reducing Agent:**
- Lithium Aluminium Hydride (LiAlH4) is a strong reducing agent that can reduce various functional groups including aldehydes, ketones, carboxylic acids, esters, and amides.

2. **Identify the Compounds:**
- We need to analyze the compounds provided in the question. Let's assume the compounds are:
1. Cyclohexanone
2. 2-Methyl-1-butanol
3. Ethyl benzoate
4. Caprolactam

3. **Analyze Each Compound:**
- **Cyclohexanone:**
- This is a ketone and will be reduced by LiAlH4 to form cyclohexanol.
- **Conclusion:** This compound is reduced.

- **2-Methyl-1-butanol:**
- This is an alcohol. LiAlH4 does not reduce alcohols, so no reaction will occur.
- **Conclusion:** This compound is NOT reduced.

- **Ethyl benzoate:**
- This is an ester. LiAlH4 can reduce esters to alcohols.
- **Conclusion:** This compound is reduced.

- **Caprolactam:**
- This is a cyclic amide (lactam). LiAlH4 can reduce amides, so it will also be reduced.
- **Conclusion:** This compound is reduced.

4. **Final Conclusion:**
- The only compound that is not reduced by LiAlH4 is **2-Methyl-1-butanol**.

### Answer:
The compound which is not reduced by LiAlH4 is **2-Methyl-1-butanol**.