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Conductivity of 0.003 M sulphuric acid i...

Conductivity of 0.003 M sulphuric acid is `6.896xx10^(-5)"S "cm^(-1)`. Calculate its molar conductivity and if` wedge^(@)m` for sulphuric acid is 490.5 `Scm^(2)mol^(-1)`, what is its dissociation constant?

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To solve the problem step by step, we will calculate the molar conductivity of sulfuric acid and then find its dissociation constant. ### Step 1: Calculate Molar Conductivity The formula for molar conductivity (Λ) is given by: \[ \Lambda = \frac{K \times 1000}{C} ...
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