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(.^(n)C(0))^(2)+(.^(n)C(1))^(2)+(.^(n)C(...

`(.^(n)C_(0))^(2)+(.^(n)C_(1))^(2)+(.^(n)C_(2))^(2)+ . . .+(.^(n)C_(n))^(2)` equals

A

0 if n is odd

B

`(-1)^(n)` if n is odd

C

`(-1)^(n//2).^(n)C_(n//2)` if n is even

D

`(-1)^(n-1).^(n)C_(n-1)` if n is even

Text Solution

Verified by Experts

The correct Answer is:
A, C
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