Find minium value of `(9x^(2)sin^(2)x+4)/(2sinx.x)` in the interval `0 le x le pi`.

Explanation

To find the minimum value of the expression

\[ f(x) = \frac{9x^2 \sin^2 x + 4}{2 \sin x \cdot x} \]

in the interval \(0 \leq x \leq \pi\), we can follow these steps:

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