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Prove that: (sin5A-sin3A)/(cos5A+cos3A)=...

Prove that: `(sin5A-sin3A)/(cos5A+cos3A)=tanA` (2)`(sinA+sin3A)/(cosA+cos3A)=tan2A`

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We have,
LHS = `(sin5A-sin3A)/(cos5A+cos3A)`
`=(2sin(5A-3A)/2cos(5A+3A)/(2))/(2cos (5A+3A)/(2)cos(5A-3A)/(2)) = (2sinAcos4A)/(2cos4AcosA)=tanA`=RHS
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